Finding half a diagonal in a rhombus using trigonometric ratios?

Finding half a diagonal in a rhombus using trigonometric ratios?

So, if you take a rhombus, then call the bottom left hand corner $A$, the
top left hand corner $B$, the top right hand corner $C$, and the bottom
right hand corner $D$. Then draw the two diagonals.
The angle of the bottom left hand corner is $60°$. The side lengths are
$10$ cm. Call the point where the diagonals bisect each other $X$. I have
to find the distance of $AX$.